6(a+3)=2(a+1)

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Solution for 6(a+3)=2(a+1) equation: 



6(a+3)=2(a+1)

We move all terms to the left:

6(a+3)-(2(a+1))=0

We multiply parentheses

6a-(2(a+1))+18=0



We calculate terms in parentheses: -(2(a+1)), so:

2(a+1)

We multiply parentheses

2a+2

Back to the equation:

-(2a+2)



We get rid of parentheses

6a-2a-2+18=0

We add all the numbers together, and all the variables

4a+16=0

We move all terms containing a to the left, all other terms to the right

4a=-16

a=-16/4

a=-4

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