6(a+4)/9=4(a-4)/12

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Solution for 6(a+4)/9=4(a-4)/12 equation: 



6(a+4)/9=4(a-4)/12

We move all terms to the left:

6(a+4)/9-(4(a-4)/12)=0

We calculate fractions


6a/()+(-(4(a-4)*9)/()=0



We calculate terms in parentheses: +(-(4(a-4)*9)/(), so:

-(4(a-4)*9)/(

We multiply all the terms by the denominator


-(4(a-4)*9)



We calculate terms in parentheses: -(4(a-4)*9), so:

4(a-4)*9

We multiply parentheses

36a-144

Back to the equation:

-(36a-144)



We get rid of parentheses

-36a+144

Back to the equation:

+(-36a+144)



We get rid of parentheses

6a/()-36a+144=0

We multiply all the terms by the denominator


6a-36a*()+144*()=0

We add all the numbers together, and all the variables

6a-36a*()=0

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