6(a+7)+2(3a-5)=-40

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Solution for 6(a+7)+2(3a-5)=-40 equation: 



6(a+7)+2(3a-5)=-40

We move all terms to the left:

6(a+7)+2(3a-5)-(-40)=0

We add all the numbers together, and all the variables

6(a+7)+2(3a-5)+40=0

We multiply parentheses

6a+6a+42-10+40=0

We add all the numbers together, and all the variables

12a+72=0

We move all terms containing a to the left, all other terms to the right

12a=-72

a=-72/12

a=-6

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