6(a-3)+10=2(3a-4)

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Solution for 6(a-3)+10=2(3a-4) equation:


Simplifying
6(a + -3) + 10 = 2(3a + -4)

Reorder the terms:
6(-3 + a) + 10 = 2(3a + -4)
(-3 * 6 + a * 6) + 10 = 2(3a + -4)
(-18 + 6a) + 10 = 2(3a + -4)

Reorder the terms:
-18 + 10 + 6a = 2(3a + -4)

Combine like terms: -18 + 10 = -8
-8 + 6a = 2(3a + -4)

Reorder the terms:
-8 + 6a = 2(-4 + 3a)
-8 + 6a = (-4 * 2 + 3a * 2)
-8 + 6a = (-8 + 6a)

Add '8' to each side of the equation.
-8 + 8 + 6a = -8 + 8 + 6a

Combine like terms: -8 + 8 = 0
0 + 6a = -8 + 8 + 6a
6a = -8 + 8 + 6a

Combine like terms: -8 + 8 = 0
6a = 0 + 6a
6a = 6a

Add '-6a' to each side of the equation.
6a + -6a = 6a + -6a

Combine like terms: 6a + -6a = 0
0 = 6a + -6a

Combine like terms: 6a + -6a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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