6(a-3)+2a=9(a+6)+3(a-4)

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Solution for 6(a-3)+2a=9(a+6)+3(a-4) equation: 



6(a-3)+2a=9(a+6)+3(a-4)

We move all terms to the left:

6(a-3)+2a-(9(a+6)+3(a-4))=0

We add all the numbers together, and all the variables

2a+6(a-3)-(9(a+6)+3(a-4))=0

We multiply parentheses

2a+6a-(9(a+6)+3(a-4))-18=0



We calculate terms in parentheses: -(9(a+6)+3(a-4)), so:

9(a+6)+3(a-4)

We multiply parentheses

9a+3a+54-12

We add all the numbers together, and all the variables

12a+42

Back to the equation:

-(12a+42)



We add all the numbers together, and all the variables

8a-(12a+42)-18=0

We get rid of parentheses

8a-12a-42-18=0

We add all the numbers together, and all the variables

-4a-60=0

We move all terms containing a to the left, all other terms to the right

-4a=60

a=60/-4

a=-15

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