6(a-4)+5(2-a)=3-(-a-1)-3(a-2)

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Solution for 6(a-4)+5(2-a)=3-(-a-1)-3(a-2) equation: 



6(a-4)+5(2-a)=3-(-a-1)-3(a-2)

We move all terms to the left:

6(a-4)+5(2-a)-(3-(-a-1)-3(a-2))=0

We add all the numbers together, and all the variables

6(a-4)+5(-1a+2)-(3-(-1a-1)-3(a-2))=0

We multiply parentheses

6a-5a-(3-(-1a-1)-3(a-2))-24+10=0



We calculate terms in parentheses: -(3-(-1a-1)-3(a-2)), so:

3-(-1a-1)-3(a-2)

determiningTheFunctionDomain
-(-1a-1)-3(a-2)+3

We multiply parentheses

-(-1a-1)-3a+6+3

We get rid of parentheses

1a-3a+1+6+3

We add all the numbers together, and all the variables

-2a+10

Back to the equation:

-(-2a+10)



We add all the numbers together, and all the variables

a-(-2a+10)-14=0

We get rid of parentheses

a+2a-10-14=0

We add all the numbers together, and all the variables

3a-24=0

We move all terms containing a to the left, all other terms to the right

3a=24

a=24/3

a=8

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