6(a-5)+10=2(a-4)

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Solution for 6(a-5)+10=2(a-4) equation:


Simplifying
6(a + -5) + 10 = 2(a + -4)

Reorder the terms:
6(-5 + a) + 10 = 2(a + -4)
(-5 * 6 + a * 6) + 10 = 2(a + -4)
(-30 + 6a) + 10 = 2(a + -4)

Reorder the terms:
-30 + 10 + 6a = 2(a + -4)

Combine like terms: -30 + 10 = -20
-20 + 6a = 2(a + -4)

Reorder the terms:
-20 + 6a = 2(-4 + a)
-20 + 6a = (-4 * 2 + a * 2)
-20 + 6a = (-8 + 2a)

Solving
-20 + 6a = -8 + 2a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2a' to each side of the equation.
-20 + 6a + -2a = -8 + 2a + -2a

Combine like terms: 6a + -2a = 4a
-20 + 4a = -8 + 2a + -2a

Combine like terms: 2a + -2a = 0
-20 + 4a = -8 + 0
-20 + 4a = -8

Add '20' to each side of the equation.
-20 + 20 + 4a = -8 + 20

Combine like terms: -20 + 20 = 0
0 + 4a = -8 + 20
4a = -8 + 20

Combine like terms: -8 + 20 = 12
4a = 12

Divide each side by '4'.
a = 3

Simplifying
a = 3

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