6(a-5)+12=2(a-7)

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Solution for 6(a-5)+12=2(a-7) equation: 



6(a-5)+12=2(a-7)

We move all terms to the left:

6(a-5)+12-(2(a-7))=0

We multiply parentheses

6a-(2(a-7))-30+12=0



We calculate terms in parentheses: -(2(a-7)), so:

2(a-7)

We multiply parentheses

2a-14

Back to the equation:

-(2a-14)



We add all the numbers together, and all the variables

6a-(2a-14)-18=0

We get rid of parentheses

6a-2a+14-18=0

We add all the numbers together, and all the variables

4a-4=0

We move all terms containing a to the left, all other terms to the right

4a=4

a=4/4

a=1

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