6(a-5)+12=4(a-4)

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Solution for 6(a-5)+12=4(a-4) equation:


Simplifying
6(a + -5) + 12 = 4(a + -4)

Reorder the terms:
6(-5 + a) + 12 = 4(a + -4)
(-5 * 6 + a * 6) + 12 = 4(a + -4)
(-30 + 6a) + 12 = 4(a + -4)

Reorder the terms:
-30 + 12 + 6a = 4(a + -4)

Combine like terms: -30 + 12 = -18
-18 + 6a = 4(a + -4)

Reorder the terms:
-18 + 6a = 4(-4 + a)
-18 + 6a = (-4 * 4 + a * 4)
-18 + 6a = (-16 + 4a)

Solving
-18 + 6a = -16 + 4a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-4a' to each side of the equation.
-18 + 6a + -4a = -16 + 4a + -4a

Combine like terms: 6a + -4a = 2a
-18 + 2a = -16 + 4a + -4a

Combine like terms: 4a + -4a = 0
-18 + 2a = -16 + 0
-18 + 2a = -16

Add '18' to each side of the equation.
-18 + 18 + 2a = -16 + 18

Combine like terms: -18 + 18 = 0
0 + 2a = -16 + 18
2a = -16 + 18

Combine like terms: -16 + 18 = 2
2a = 2

Divide each side by '2'.
a = 1

Simplifying
a = 1

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