6(a-5)+4(3a+1)=24

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Solution for 6(a-5)+4(3a+1)=24 equation: 



6(a-5)+4(3a+1)=24

We move all terms to the left:

6(a-5)+4(3a+1)-(24)=0

We multiply parentheses

6a+12a-30+4-24=0

We add all the numbers together, and all the variables

18a-50=0

We move all terms containing a to the left, all other terms to the right

18a=50

a=50/18

a=2+7/9

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