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6(a-5)=3(3a)+2(a-25)
We move all terms to the left:
6(a-5)-(3(3a)+2(a-25))=0
We multiply parentheses
6a-(33a+2(a-25))-30=0
We calculate terms in parentheses: -(33a+2(a-25)), so:We get rid of parentheses
33a+2(a-25)
We multiply parentheses
33a+2a-50
We add all the numbers together, and all the variables
35a-50
Back to the equation:
-(35a-50)
6a-35a+50-30=0
We add all the numbers together, and all the variables
-29a+20=0
We move all terms containing a to the left, all other terms to the right
-29a=-20
a=-20/-29
a=20/29
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