6(a-7)+10=2(a-4)

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Solution for 6(a-7)+10=2(a-4) equation: 



6(a-7)+10=2(a-4)

We move all terms to the left:

6(a-7)+10-(2(a-4))=0

We multiply parentheses

6a-(2(a-4))-42+10=0



We calculate terms in parentheses: -(2(a-4)), so:

2(a-4)

We multiply parentheses

2a-8

Back to the equation:

-(2a-8)



We add all the numbers together, and all the variables

6a-(2a-8)-32=0

We get rid of parentheses

6a-2a+8-32=0

We add all the numbers together, and all the variables

4a-24=0

We move all terms containing a to the left, all other terms to the right

4a=24

a=24/4

a=6

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