6(b+1)-2=5(b-3)

Solution for 6(b+1)-2=5(b-3) equation:

Simplifying
6(b + 1) + -2 = 5(b + -3)

Reorder the terms:
6(1 + b) + -2 = 5(b + -3)
(1 * 6 + b * 6) + -2 = 5(b + -3)
(6 + 6b) + -2 = 5(b + -3)

Reorder the terms:
6 + -2 + 6b = 5(b + -3)

Combine like terms: 6 + -2 = 4
4 + 6b = 5(b + -3)

Reorder the terms:
4 + 6b = 5(-3 + b)
4 + 6b = (-3 * 5 + b * 5)
4 + 6b = (-15 + 5b)

Solving
4 + 6b = -15 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
4 + 6b + -5b = -15 + 5b + -5b

Combine like terms: 6b + -5b = 1b
4 + 1b = -15 + 5b + -5b

Combine like terms: 5b + -5b = 0
4 + 1b = -15 + 0
4 + 1b = -15

Add '-4' to each side of the equation.
4 + -4 + 1b = -15 + -4

Combine like terms: 4 + -4 = 0
0 + 1b = -15 + -4
1b = -15 + -4

Combine like terms: -15 + -4 = -19
1b = -19

Divide each side by '1'.
b = -19

Simplifying
b = -19