6(b+1)=7b-2

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Solution for 6(b+1)=7b-2 equation: 



6(b+1)=7b-2

We move all terms to the left:

6(b+1)-(7b-2)=0

We multiply parentheses

6b-(7b-2)+6=0

We get rid of parentheses

6b-7b+2+6=0

We add all the numbers together, and all the variables

-1b+8=0

We move all terms containing b to the left, all other terms to the right

-b=-8

b=-8/-1

b=+8

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