6(b+2)+3(b+1)=25

Solution for 6(b+2)+3(b+1)=25 equation:

Simplifying
6(b + 2) + 3(b + 1) = 25

Reorder the terms:
6(2 + b) + 3(b + 1) = 25
(2 * 6 + b * 6) + 3(b + 1) = 25
(12 + 6b) + 3(b + 1) = 25

Reorder the terms:
12 + 6b + 3(1 + b) = 25
12 + 6b + (1 * 3 + b * 3) = 25
12 + 6b + (3 + 3b) = 25

Reorder the terms:
12 + 3 + 6b + 3b = 25

Combine like terms: 12 + 3 = 15
15 + 6b + 3b = 25

Combine like terms: 6b + 3b = 9b
15 + 9b = 25

Solving
15 + 9b = 25

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-15' to each side of the equation.
15 + -15 + 9b = 25 + -15

Combine like terms: 15 + -15 = 0
0 + 9b = 25 + -15
9b = 25 + -15

Combine like terms: 25 + -15 = 10
9b = 10

Divide each side by '9'.
b = 1.111111111

Simplifying
b = 1.111111111