6(b+2)-4b=24

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Solution for 6(b+2)-4b=24 equation: 



6(b+2)-4b=24

We move all terms to the left:

6(b+2)-4b-(24)=0

We add all the numbers together, and all the variables

-4b+6(b+2)-24=0

We multiply parentheses

-4b+6b+12-24=0

We add all the numbers together, and all the variables

2b-12=0

We move all terms containing b to the left, all other terms to the right

2b=12

b=12/2

b=6

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