6(b+2)=3(b-1)

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Solution for 6(b+2)=3(b-1) equation: 



6(b+2)=3(b-1)

We move all terms to the left:

6(b+2)-(3(b-1))=0

We multiply parentheses

6b-(3(b-1))+12=0



We calculate terms in parentheses: -(3(b-1)), so:

3(b-1)

We multiply parentheses

3b-3

Back to the equation:

-(3b-3)



We get rid of parentheses

6b-3b+3+12=0

We add all the numbers together, and all the variables

3b+15=0

We move all terms containing b to the left, all other terms to the right

3b=-15

b=-15/3

b=-5

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