6(b+2)=4(b+5)

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Solution for 6(b+2)=4(b+5) equation:


Simplifying
6(b + 2) = 4(b + 5)

Reorder the terms:
6(2 + b) = 4(b + 5)
(2 * 6 + b * 6) = 4(b + 5)
(12 + 6b) = 4(b + 5)

Reorder the terms:
12 + 6b = 4(5 + b)
12 + 6b = (5 * 4 + b * 4)
12 + 6b = (20 + 4b)

Solving
12 + 6b = 20 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
12 + 6b + -4b = 20 + 4b + -4b

Combine like terms: 6b + -4b = 2b
12 + 2b = 20 + 4b + -4b

Combine like terms: 4b + -4b = 0
12 + 2b = 20 + 0
12 + 2b = 20

Add '-12' to each side of the equation.
12 + -12 + 2b = 20 + -12

Combine like terms: 12 + -12 = 0
0 + 2b = 20 + -12
2b = 20 + -12

Combine like terms: 20 + -12 = 8
2b = 8

Divide each side by '2'.
b = 4

Simplifying
b = 4

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