6(b+2)=6c+12

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Solution for 6(b+2)=6c+12 equation:


Simplifying
6(b + 2) = 6c + 12

Reorder the terms:
6(2 + b) = 6c + 12
(2 * 6 + b * 6) = 6c + 12
(12 + 6b) = 6c + 12

Reorder the terms:
12 + 6b = 12 + 6c

Add '-12' to each side of the equation.
12 + -12 + 6b = 12 + -12 + 6c

Combine like terms: 12 + -12 = 0
0 + 6b = 12 + -12 + 6c
6b = 12 + -12 + 6c

Combine like terms: 12 + -12 = 0
6b = 0 + 6c
6b = 6c

Solving
6b = 6c

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Divide each side by '6'.
b = c

Simplifying
b = c

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