6(b+2)=7b+5

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Solution for 6(b+2)=7b+5 equation:



6(b+2)=7b+5
We move all terms to the left:
6(b+2)-(7b+5)=0
We multiply parentheses
6b-(7b+5)+12=0
We get rid of parentheses
6b-7b-5+12=0
We add all the numbers together, and all the variables
-1b+7=0
We move all terms containing b to the left, all other terms to the right
-b=-7
b=-7/-1
b=+7

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