6(b+2)=7b+5

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Solution for 6(b+2)=7b+5 equation: 



6(b+2)=7b+5

We move all terms to the left:

6(b+2)-(7b+5)=0

We multiply parentheses

6b-(7b+5)+12=0

We get rid of parentheses

6b-7b-5+12=0

We add all the numbers together, and all the variables

-1b+7=0

We move all terms containing b to the left, all other terms to the right

-b=-7

b=-7/-1

b=+7

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