6(b+3)-2(-2b+4)=0

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Solution for 6(b+3)-2(-2b+4)=0 equation: 



6(b+3)-2(-2b+4)=0

We multiply parentheses

6b+4b+18-8=0

We add all the numbers together, and all the variables

10b+10=0

We move all terms containing b to the left, all other terms to the right

10b=-10

b=-10/10

b=-1

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