6(b+8)=12-4b

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Solution for 6(b+8)=12-4b equation: 



6(b+8)=12-4b

We move all terms to the left:

6(b+8)-(12-4b)=0

We add all the numbers together, and all the variables

6(b+8)-(-4b+12)=0

We multiply parentheses

6b-(-4b+12)+48=0

We get rid of parentheses

6b+4b-12+48=0

We add all the numbers together, and all the variables

10b+36=0

We move all terms containing b to the left, all other terms to the right

10b=-36

b=-36/10

b=-3+3/5

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