6(b-10)=-6(b+2)

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Solution for 6(b-10)=-6(b+2) equation: 



6(b-10)=-6(b+2)

We move all terms to the left:

6(b-10)-(-6(b+2))=0

We multiply parentheses

6b-(-6(b+2))-60=0



We calculate terms in parentheses: -(-6(b+2)), so:

-6(b+2)

We multiply parentheses

-6b-12

Back to the equation:

-(-6b-12)



We get rid of parentheses

6b+6b+12-60=0

We add all the numbers together, and all the variables

12b-48=0

We move all terms containing b to the left, all other terms to the right

12b=48

b=48/12

b=4

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