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6(b-2)+4=2+2(1+6b)
We move all terms to the left:
6(b-2)+4-(2+2(1+6b))=0
We add all the numbers together, and all the variables
6(b-2)-(2+2(6b+1))+4=0
We multiply parentheses
6b-(2+2(6b+1))-12+4=0
We calculate terms in parentheses: -(2+2(6b+1)), so:We add all the numbers together, and all the variables
2+2(6b+1)
determiningTheFunctionDomain 2(6b+1)+2
We multiply parentheses
12b+2+2
We add all the numbers together, and all the variables
12b+4
Back to the equation:
-(12b+4)
6b-(12b+4)-8=0
We get rid of parentheses
6b-12b-4-8=0
We add all the numbers together, and all the variables
-6b-12=0
We move all terms containing b to the left, all other terms to the right
-6b=12
b=12/-6
b=-2
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