6(b-2)+4=2+2(1+6b)

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Solution for 6(b-2)+4=2+2(1+6b) equation: 



6(b-2)+4=2+2(1+6b)

We move all terms to the left:

6(b-2)+4-(2+2(1+6b))=0

We add all the numbers together, and all the variables

6(b-2)-(2+2(6b+1))+4=0

We multiply parentheses

6b-(2+2(6b+1))-12+4=0



We calculate terms in parentheses: -(2+2(6b+1)), so:

2+2(6b+1)

determiningTheFunctionDomain
2(6b+1)+2

We multiply parentheses

12b+2+2

We add all the numbers together, and all the variables

12b+4

Back to the equation:

-(12b+4)



We add all the numbers together, and all the variables

6b-(12b+4)-8=0

We get rid of parentheses

6b-12b-4-8=0

We add all the numbers together, and all the variables

-6b-12=0

We move all terms containing b to the left, all other terms to the right

-6b=12

b=12/-6

b=-2

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