6(b-2)=2z+40

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Solution for 6(b-2)=2z+40 equation:


Simplifying
6(b + -2) = 2z + 40

Reorder the terms:
6(-2 + b) = 2z + 40
(-2 * 6 + b * 6) = 2z + 40
(-12 + 6b) = 2z + 40

Reorder the terms:
-12 + 6b = 40 + 2z

Solving
-12 + 6b = 40 + 2z

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 6b = 40 + 12 + 2z

Combine like terms: -12 + 12 = 0
0 + 6b = 40 + 12 + 2z
6b = 40 + 12 + 2z

Combine like terms: 40 + 12 = 52
6b = 52 + 2z

Divide each side by '6'.
b = 8.666666667 + 0.3333333333z

Simplifying
b = 8.666666667 + 0.3333333333z

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