6(b-2)=5(9+b)

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Solution for 6(b-2)=5(9+b) equation: 



6(b-2)=5(9+b)

We move all terms to the left:

6(b-2)-(5(9+b))=0

We add all the numbers together, and all the variables

6(b-2)-(5(b+9))=0

We multiply parentheses

6b-(5(b+9))-12=0



We calculate terms in parentheses: -(5(b+9)), so:

5(b+9)

We multiply parentheses

5b+45

Back to the equation:

-(5b+45)



We get rid of parentheses

6b-5b-45-12=0

We add all the numbers together, and all the variables

b-57=0

We move all terms containing b to the left, all other terms to the right

b=57

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