6(b-3)=2(2b-4)

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Solution for 6(b-3)=2(2b-4) equation: 



6(b-3)=2(2b-4)

We move all terms to the left:

6(b-3)-(2(2b-4))=0

We multiply parentheses

6b-(2(2b-4))-18=0



We calculate terms in parentheses: -(2(2b-4)), so:

2(2b-4)

We multiply parentheses

4b-8

Back to the equation:

-(4b-8)



We get rid of parentheses

6b-4b+8-18=0

We add all the numbers together, and all the variables

2b-10=0

We move all terms containing b to the left, all other terms to the right

2b=10

b=10/2

b=5

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