6(b-3)=2(2b-4)

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Solution for 6(b-3)=2(2b-4) equation:



6(b-3)=2(2b-4)
We move all terms to the left:
6(b-3)-(2(2b-4))=0
We multiply parentheses
6b-(2(2b-4))-18=0
We calculate terms in parentheses: -(2(2b-4)), so:
2(2b-4)
We multiply parentheses
4b-8
Back to the equation:
-(4b-8)
We get rid of parentheses
6b-4b+8-18=0
We add all the numbers together, and all the variables
2b-10=0
We move all terms containing b to the left, all other terms to the right
2b=10
b=10/2
b=5

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