6(b-3)=3(b-6)

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Solution for 6(b-3)=3(b-6) equation: 



6(b-3)=3(b-6)

We move all terms to the left:

6(b-3)-(3(b-6))=0

We multiply parentheses

6b-(3(b-6))-18=0



We calculate terms in parentheses: -(3(b-6)), so:

3(b-6)

We multiply parentheses

3b-18

Back to the equation:

-(3b-18)



We get rid of parentheses

6b-3b+18-18=0

We add all the numbers together, and all the variables

3b=0

b=0/3

b=0

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