6(b-4)+5b=44

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Solution for 6(b-4)+5b=44 equation: 



6(b-4)+5b=44

We move all terms to the left:

6(b-4)+5b-(44)=0

We add all the numbers together, and all the variables

5b+6(b-4)-44=0

We multiply parentheses

5b+6b-24-44=0

We add all the numbers together, and all the variables

11b-68=0

We move all terms containing b to the left, all other terms to the right

11b=68

b=68/11

b=6+2/11

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