6(b-4)=3(b+6)

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Solution for 6(b-4)=3(b+6) equation: 



6(b-4)=3(b+6)

We move all terms to the left:

6(b-4)-(3(b+6))=0

We multiply parentheses

6b-(3(b+6))-24=0



We calculate terms in parentheses: -(3(b+6)), so:

3(b+6)

We multiply parentheses

3b+18

Back to the equation:

-(3b+18)



We get rid of parentheses

6b-3b-18-24=0

We add all the numbers together, and all the variables

3b-42=0

We move all terms containing b to the left, all other terms to the right

3b=42

b=42/3

b=14

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