6(b-7)+4(-6b+3)=42

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Solution for 6(b-7)+4(-6b+3)=42 equation: 



6(b-7)+4(-6b+3)=42

We move all terms to the left:

6(b-7)+4(-6b+3)-(42)=0

We multiply parentheses

6b-24b-42+12-42=0

We add all the numbers together, and all the variables

-18b-72=0

We move all terms containing b to the left, all other terms to the right

-18b=72

b=72/-18

b=-4

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