6(b-8)=3(7b-5)

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Solution for 6(b-8)=3(7b-5) equation: 



6(b-8)=3(7b-5)

We move all terms to the left:

6(b-8)-(3(7b-5))=0

We multiply parentheses

6b-(3(7b-5))-48=0



We calculate terms in parentheses: -(3(7b-5)), so:

3(7b-5)

We multiply parentheses

21b-15

Back to the equation:

-(21b-15)



We get rid of parentheses

6b-21b+15-48=0

We add all the numbers together, and all the variables

-15b-33=0

We move all terms containing b to the left, all other terms to the right

-15b=33

b=33/-15

b=-2+1/5

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