6(c+1)-4=12c-4(2c-1)

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Solution for 6(c+1)-4=12c-4(2c-1) equation: 



6(c+1)-4=12c-4(2c-1)

We move all terms to the left:

6(c+1)-4-(12c-4(2c-1))=0

We multiply parentheses

6c-(12c-4(2c-1))+6-4=0



We calculate terms in parentheses: -(12c-4(2c-1)), so:

12c-4(2c-1)

We multiply parentheses

12c-8c+4

We add all the numbers together, and all the variables

4c+4

Back to the equation:

-(4c+4)



We add all the numbers together, and all the variables

6c-(4c+4)+2=0

We get rid of parentheses

6c-4c-4+2=0

We add all the numbers together, and all the variables

2c-2=0

We move all terms containing c to the left, all other terms to the right

2c=2

c=2/2

c=1

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