6(c+2)+15=63

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Solution for 6(c+2)+15=63 equation: 



6(c+2)+15=63

We move all terms to the left:

6(c+2)+15-(63)=0

We add all the numbers together, and all the variables

6(c+2)-48=0

We multiply parentheses

6c+12-48=0

We add all the numbers together, and all the variables

6c-36=0

We move all terms containing c to the left, all other terms to the right

6c=36

c=36/6

c=6

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