6(c+2)=6c=12

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Solution for 6(c+2)=6c=12 equation: 



6(c+2)=6c=12

We move all terms to the left:

6(c+2)-(6c)=0

We add all the numbers together, and all the variables

-6c+6(c+2)=0

We multiply parentheses

-6c+6c+12=0

We add all the numbers together, and all the variables

12!=0

There is no solution for this equation

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