6(c+3)+4(1-c)=

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Solution for 6(c+3)+4(1-c)= equation:


Simplifying
6(c + 3) + 4(1 + -1c) = 0

Reorder the terms:
6(3 + c) + 4(1 + -1c) = 0
(3 * 6 + c * 6) + 4(1 + -1c) = 0
(18 + 6c) + 4(1 + -1c) = 0
18 + 6c + (1 * 4 + -1c * 4) = 0
18 + 6c + (4 + -4c) = 0

Reorder the terms:
18 + 4 + 6c + -4c = 0

Combine like terms: 18 + 4 = 22
22 + 6c + -4c = 0

Combine like terms: 6c + -4c = 2c
22 + 2c = 0

Solving
22 + 2c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-22' to each side of the equation.
22 + -22 + 2c = 0 + -22

Combine like terms: 22 + -22 = 0
0 + 2c = 0 + -22
2c = 0 + -22

Combine like terms: 0 + -22 = -22
2c = -22

Divide each side by '2'.
c = -11

Simplifying
c = -11

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