6(c+3)+c=6c+3+15

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Solution for 6(c+3)+c=6c+3+15 equation: 



6(c+3)+c=6c+3+15

We move all terms to the left:

6(c+3)+c-(6c+3+15)=0

We add all the numbers together, and all the variables

6(c+3)+c-(6c+18)=0

We add all the numbers together, and all the variables

c+6(c+3)-(6c+18)=0

We multiply parentheses

c+6c-(6c+18)+18=0

We get rid of parentheses

c+6c-6c-18+18=0

We add all the numbers together, and all the variables

c=0

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