6(c+3)+c=7c+2+1

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Solution for 6(c+3)+c=7c+2+1 equation: 



6(c+3)+c=7c+2+1

We move all terms to the left:

6(c+3)+c-(7c+2+1)=0

We add all the numbers together, and all the variables

6(c+3)+c-(7c+3)=0

We add all the numbers together, and all the variables

c+6(c+3)-(7c+3)=0

We multiply parentheses

c+6c-(7c+3)+18=0

We get rid of parentheses

c+6c-7c-3+18=0

We add all the numbers together, and all the variables

15!=0

There is no solution for this equation

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