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6(c+3)+c=7c+2+1
We move all terms to the left:
6(c+3)+c-(7c+2+1)=0
We add all the numbers together, and all the variables
6(c+3)+c-(7c+3)=0
We add all the numbers together, and all the variables
c+6(c+3)-(7c+3)=0
We multiply parentheses
c+6c-(7c+3)+18=0
We get rid of parentheses
c+6c-7c-3+18=0
We add all the numbers together, and all the variables
15!=0
There is no solution for this equation
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