6(c+3)-2(c-2)=10

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Solution for 6(c+3)-2(c-2)=10 equation: 


Simplifying
6(c + 3) + -2(c + -2) = 10

Reorder the terms:
6(3 + c) + -2(c + -2) = 10
(3 * 6 + c * 6) + -2(c + -2) = 10
(18 + 6c) + -2(c + -2) = 10

Reorder the terms:
18 + 6c + -2(-2 + c) = 10
18 + 6c + (-2 * -2 + c * -2) = 10
18 + 6c + (4 + -2c) = 10

Reorder the terms:
18 + 4 + 6c + -2c = 10

Combine like terms: 18 + 4 = 22
22 + 6c + -2c = 10

Combine like terms: 6c + -2c = 4c
22 + 4c = 10

Solving
22 + 4c = 10

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-22' to each side of the equation.
22 + -22 + 4c = 10 + -22

Combine like terms: 22 + -22 = 0
0 + 4c = 10 + -22
4c = 10 + -22

Combine like terms: 10 + -22 = -12
4c = -12

Divide each side by '4'.
c = -3

Simplifying
c = -3

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