6(c+4)=2(2c-9)

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Solution for 6(c+4)=2(2c-9) equation: 



6(c+4)=2(2c-9)

We move all terms to the left:

6(c+4)-(2(2c-9))=0

We multiply parentheses

6c-(2(2c-9))+24=0



We calculate terms in parentheses: -(2(2c-9)), so:

2(2c-9)

We multiply parentheses

4c-18

Back to the equation:

-(4c-18)



We get rid of parentheses

6c-4c+18+24=0

We add all the numbers together, and all the variables

2c+42=0

We move all terms containing c to the left, all other terms to the right

2c=-42

c=-42/2

c=-21

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