6(c+4)=5c-18

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Solution for 6(c+4)=5c-18 equation: 



6(c+4)=5c-18

We move all terms to the left:

6(c+4)-(5c-18)=0

We multiply parentheses

6c-(5c-18)+24=0

We get rid of parentheses

6c-5c+18+24=0

We add all the numbers together, and all the variables

c+42=0

We move all terms containing c to the left, all other terms to the right

c=-42

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