6(c-1)=2(3c-3)

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Solution for 6(c-1)=2(3c-3) equation: 



6(c-1)=2(3c-3)

We move all terms to the left:

6(c-1)-(2(3c-3))=0

We multiply parentheses

6c-(2(3c-3))-6=0



We calculate terms in parentheses: -(2(3c-3)), so:

2(3c-3)

We multiply parentheses

6c-6

Back to the equation:

-(6c-6)



We get rid of parentheses

6c-6c+6-6=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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