6(c-2)+3=3c-15

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Solution for 6(c-2)+3=3c-15 equation: 



6(c-2)+3=3c-15

We move all terms to the left:

6(c-2)+3-(3c-15)=0

We multiply parentheses

6c-(3c-15)-12+3=0

We get rid of parentheses

6c-3c+15-12+3=0

We add all the numbers together, and all the variables

3c+6=0

We move all terms containing c to the left, all other terms to the right

3c=-6

c=-6/3

c=-2

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