6(c-2)-(8c+1)=0

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Solution for 6(c-2)-(8c+1)=0 equation: 



6(c-2)-(8c+1)=0

We multiply parentheses

6c-(8c+1)-12=0

We get rid of parentheses

6c-8c-1-12=0

We add all the numbers together, and all the variables

-2c-13=0

We move all terms containing c to the left, all other terms to the right

-2c=13

c=13/-2

c=-6+1/2

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