6(c-3)+7=3+c-14

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Solution for 6(c-3)+7=3+c-14 equation: 


Simplifying
6(c + -3) + 7 = 3 + c + -14

Reorder the terms:
6(-3 + c) + 7 = 3 + c + -14
(-3 * 6 + c * 6) + 7 = 3 + c + -14
(-18 + 6c) + 7 = 3 + c + -14

Reorder the terms:
-18 + 7 + 6c = 3 + c + -14

Combine like terms: -18 + 7 = -11
-11 + 6c = 3 + c + -14

Reorder the terms:
-11 + 6c = 3 + -14 + c

Combine like terms: 3 + -14 = -11
-11 + 6c = -11 + c

Add '11' to each side of the equation.
-11 + 11 + 6c = -11 + 11 + c

Combine like terms: -11 + 11 = 0
0 + 6c = -11 + 11 + c
6c = -11 + 11 + c

Combine like terms: -11 + 11 = 0
6c = 0 + c
6c = c

Solving
6c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
6c + -1c = c + -1c

Combine like terms: 6c + -1c = 5c
5c = c + -1c

Combine like terms: c + -1c = 0
5c = 0

Divide each side by '5'.
c = 0

Simplifying
c = 0

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