6(c-3)+8=2+c-12

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Solution for 6(c-3)+8=2+c-12 equation:



6(c-3)+8=2+c-12
We move all terms to the left:
6(c-3)+8-(2+c-12)=0
We add all the numbers together, and all the variables
6(c-3)-(c-10)+8=0
We multiply parentheses
6c-(c-10)-18+8=0
We get rid of parentheses
6c-c+10-18+8=0
We add all the numbers together, and all the variables
5c=0
c=0/5
c=0

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