6(c-3)+8=2+c-12

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Solution for 6(c-3)+8=2+c-12 equation: 



6(c-3)+8=2+c-12

We move all terms to the left:

6(c-3)+8-(2+c-12)=0

We add all the numbers together, and all the variables

6(c-3)-(c-10)+8=0

We multiply parentheses

6c-(c-10)-18+8=0

We get rid of parentheses

6c-c+10-18+8=0

We add all the numbers together, and all the variables

5c=0

c=0/5

c=0

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