6(c-3)=2(c+2)-(c-8)

Solution for 6(c-3)=2(c+2)-(c-8) equation:

6(c-3)=2(c+2)-(c-8)

We simplify the equation to the form, which is simple to understand 
6(c-3)=2(c+2)-(c-8)

Reorder the terms in parentheses
+(+6c-18)=2*(c+2)-(c-8)

Remove unnecessary parentheses
+6c-18=+2+*(+c+2+)-(+c-8+)

Reorder the terms in parentheses
+6c-18=+(+2c+4)-(c-8)

Remove unnecessary parentheses
+6c-18=+2c+4-(+c-8+)

Remove unnecessary parentheses
+6c-18=+2c+4-1c+8

We move all terms containing c to the left and all other terms to the right. 
+6c-2c+1c=+4+8+18

We simplify left and right side of the equation. 
+5c=+30

We divide both sides of the equation by 5 to get c. 
c=6