6(c-5)+5=4+c-29

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Solution for 6(c-5)+5=4+c-29 equation: 



6(c-5)+5=4+c-29

We move all terms to the left:

6(c-5)+5-(4+c-29)=0

We add all the numbers together, and all the variables

6(c-5)-(c-25)+5=0

We multiply parentheses

6c-(c-25)-30+5=0

We get rid of parentheses

6c-c+25-30+5=0

We add all the numbers together, and all the variables

5c=0

c=0/5

c=0

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