6(c-5)+9=2+c-23

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Solution for 6(c-5)+9=2+c-23 equation: 



6(c-5)+9=2+c-23

We move all terms to the left:

6(c-5)+9-(2+c-23)=0

We add all the numbers together, and all the variables

6(c-5)-(c-21)+9=0

We multiply parentheses

6c-(c-21)-30+9=0

We get rid of parentheses

6c-c+21-30+9=0

We add all the numbers together, and all the variables

5c=0

c=0/5

c=0

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