6(c-6)=3(3c+10)

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Solution for 6(c-6)=3(3c+10) equation: 



6(c-6)=3(3c+10)

We move all terms to the left:

6(c-6)-(3(3c+10))=0

We multiply parentheses

6c-(3(3c+10))-36=0



We calculate terms in parentheses: -(3(3c+10)), so:

3(3c+10)

We multiply parentheses

9c+30

Back to the equation:

-(9c+30)



We get rid of parentheses

6c-9c-30-36=0

We add all the numbers together, and all the variables

-3c-66=0

We move all terms containing c to the left, all other terms to the right

-3c=66

c=66/-3

c=-22

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